Talk:Robinson annulation

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How do you create a picture of chemical compounds, like showing a toluene, or a 1,3-dichloropentane? --lux 23:11, 26 Mar 2005 (UTC) Somehow we didn't answer the question by Luxdormiens for almost four years. I sure do hope he (or she) is still interested?! Let's speak about toluene, a good example. It may be said that the formula of toluene is C6H5-CH3. This adds up to the brutto formula of C7H8. This does not mean too much in the class-room. However, if we learn that C6H5- is the "phenyl group", and CH3- is the "methyl group" we are then one step ahead of the game. Now we have to learn how to draw a phenyl group and how to draw a methyl group, and connect these two groups together with a dash = a so called "single bond". The easiest way to derive to the phenyl group is to draw the formula of benzene. This formula was first drawn by a scientist named Kekule. If you draw a six membered ring with three alternating double bonds in it, you get the "picture" of the benzene ring whose formula is C6H6. Therefore, if you remove one hydrogen you obtain C6H5- that is the phenyl group. Similarily, by removing one hydrogen of methane = CH4, you obtain CH3-, the methyl group. Connecting these two gives you the "picture" of toluene. User:Zghajos —Preceding undated comment was added at 22:06, 5 February 2009 (UTC).[reply]

What is it for?[edit]

Can someone explain this for non-chemists? And why would anyone want to do this? m.e. 05:29, 9 January 2007 (UTC)[reply]

  • organic reactions are studied in schools by examining many of this type of reactions. No doubt this reaction type is useful in industry but it is certainly instructive in the class room if you want to learn about organic chemistry. Hope this answers your question V8rik 21:58, 9 January 2007 (UTC)[reply]

Working on Major Edit[edit]

I plan on making significant edits to this article over the next month as part of a project for my graduate organic chemistry class. Ehart4 (talk) 14:08, 21 October 2011 (UTC)[reply]

I've found some problems with this Wiki page

 1. An enol ether is not an electron acceptor, under "Michael Acceptors". 
 2. The michael acceptor under "Hauser annulation" is missing a carbonyl.  — Preceding unsigned comment added by 128.200.31.7 (talk) 18:09, 14 January 2015 (UTC)[reply] 

Correction 1[edit]

There is a ketone group missing on the second figure, in third and fourth step. I'll upload a corrected scheme... Well, I'll do it some other time since I am not yet allowed to upload pictures. — Preceding unsigned comment added by Jivkovic (talkcontribs) 22:07, 6 January 2012 (UTC)[reply]

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